If it's not what You are looking for type in the equation solver your own equation and let us solve it.
24+2x-1x^2=0
a = -1; b = 2; c = +24;
Δ = b2-4ac
Δ = 22-4·(-1)·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*-1}=\frac{-12}{-2} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*-1}=\frac{8}{-2} =-4 $
| 2(x-6)-5x=2x-12-5x | | (4x+7)(x-3)-(12x+21)=0 | | b^2-6b+b^2=0 | | 3×+1=h(-4) | | z/9-9=10 | | 23-6x=-19 | | (2y+5)(y+3)=-5(2y+5) | | 16-5(3t-4)=-16t+88 | | -3(2-x)+x=x-7 | | (4x+7)(x-3)=12x+21 | | -32/4=x | | x/5-8=-1 | | -2x7=7 | | -34/8=x | | -w+8=2 | | 8000=35(x)+25(x) | | 2y-8-4y=y^2-2y | | |x-7|+9=4 | | -2.7-3.4d=-24.8 | | 5x^2+10x+27=0 | | x2=-16 | | 4x-4=3x-3,5 | | 4–2s=2 | | 12*2.78^2k=6.5 | | 0.065=a/3.2 | | 2=4–2s | | 0.6(4)+0.4(x)=5.5 | | v=26+24+(-16) | | 100+x3=250 | | x/2-2=3x-30 | | 5(r+3)=2r+6. | | 0.2(4)+0.2(4)+0.4(x)=5.5 |